Two streets are parallel on a map, 7th street and 8th street. The map is put on a coordinate plane and the equation for 7th street is 𝑦 = 2𝑥 − 6. 8th street goes through the coordinates (1,3) on the map. Write an equation of the line 8th street is on.(1 point)

Responses

8th Street is on y=−12x+72
8th Street is on y is equal to negative 1 half x plus 7 halves

8th Street is on y=2x+3
8th Street is on y is equal to 2 x plus 3

8th Street is on y=2x+1
8th Street is on y is equal to 2 x plus 1

8th Street is on y=−12x+1

1 answer

Since 7th street has the equation \( y = 2x - 6 \), and 8th street is parallel to 7th street, it will have the same slope. The slope of 7th street is \( 2 \).

The equation for 8th street will be in the form \( y = mx + b \), where \( m \) is the slope. Thus, the equation for 8th street will be \( y = 2x + b \).

To find the value of \( b \), we can use the point (1, 3) which lies on 8th street. Substituting \( x = 1 \) and \( y = 3 \) into the equation:

\[ 3 = 2(1) + b \] \[ 3 = 2 + b \] \[ b = 3 - 2 \] \[ b = 1 \]

Thus, the equation of 8th street is:

\[ y = 2x + 1 \]

Therefore, the correct response is:

8th Street is on \( y = 2x + 1 \).