Since 7th street has the equation \( y = 2x - 6 \), and 8th street is parallel to 7th street, it will have the same slope. The slope of 7th street is \( 2 \).
The equation for 8th street will be in the form \( y = mx + b \), where \( m \) is the slope. Thus, the equation for 8th street will be \( y = 2x + b \).
To find the value of \( b \), we can use the point (1, 3) which lies on 8th street. Substituting \( x = 1 \) and \( y = 3 \) into the equation:
\[ 3 = 2(1) + b \] \[ 3 = 2 + b \] \[ b = 3 - 2 \] \[ b = 1 \]
Thus, the equation of 8th street is:
\[ y = 2x + 1 \]
Therefore, the correct response is:
8th Street is on \( y = 2x + 1 \).