Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. Assume free fall.

If the faster stone takes 9.00 to return to the ground, how long will it take the slower stone to return?

If the slower stone reaches a maximum height of , how high (in terms of ) will the faster stone go?

2 answers

T fast =3t slow
9=3t
T=9/3

slow stone 3s
hight

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