let h be the place where they meet. Both are in the air for the same time.
htop=6.41-8.35t-4.9t^2
hbottom=0+8.35t-4.9t^2
when they hit, htop=hbottom
subtract the equations..
0=6.41-2*835t
solve for time t at impact, then put it in either equation and solve for either htop, or hbottom.
Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The height of the cliff is 6.41 m. The stones are thrown with the same speed of 8.35 m/s. Find the location (above the base of the cliff) of the point where the stones cross paths.
2 answers
A stone is dropped off a cliff of height h. At the same time, a second stone is thrown straight upward from the base of the cliff with an initial velocity v �� i . Assuming that the second rock is thrown hard enough, at what time t will the two stones meet?