x=mg/k
spring 1, 5.9*9.81/2000=?
spring 2, 5.9*9.81/3000=?
combined= spring 1 + spring 2
I answered my own question./
two springs of constants 2.0*10^3 Nm and 3.0*10^3 Nm are connected in tandem, and a mass of 5.9kg hangs vertically from this spring. 1.) by what amount does the mass stretch the combined string? 2.) By what amount does the mass stretch each individual string?
2 answers
for springs connected in tandem
1/k=1/k1 +1/k2 =>
k=1200 N/m
the stretch is
x=mg/k=5.9•9.81/1200 =
1/k=1/k1 +1/k2 =>
k=1200 N/m
the stretch is
x=mg/k=5.9•9.81/1200 =