F = Q^2 / (4 pi eps d^2)
find Q
then the number electrons is
N = Q /e
where e is the electron's charge (look it up)
Two spherical objects are separated by a distance of 2.41 x 10-3 m. The objects are initially electrically neutral and are very small compared to the distance between them. Each object acquires the same negative charge due to the addition of electrons. As a result, each object experiences an electrostatic force that has a magnitude of 4.18 x 10-21 N. How many electrons did it take to produce the charge on one of the objects?
Can you help at all? Please give me an idea where to start. Thank you.
3 answers
The distance between them is
d = 2.41 x 10-3 m
The charge on each sphere is Q
The force of each sphere on the other is
F = k Q^2/d^2 = 4.18 x 10-21 N
Look up the Coulomb's Law constant k and solve that equation for Q.
The number of electrons is
N = Q/e
where e is the electron charge.
d = 2.41 x 10-3 m
The charge on each sphere is Q
The force of each sphere on the other is
F = k Q^2/d^2 = 4.18 x 10-21 N
Look up the Coulomb's Law constant k and solve that equation for Q.
The number of electrons is
N = Q/e
where e is the electron charge.
Ok. I did that and I found that Q= 1.64 x 10 ^ -18.
I then divided that by 1.6 x 10 ^ -19.
The answer I got was 10.23.
I am being told that is the wrong answer. Could you please double check that for me?
Thank you!!
I then divided that by 1.6 x 10 ^ -19.
The answer I got was 10.23.
I am being told that is the wrong answer. Could you please double check that for me?
Thank you!!
3 answers