The closest point?
let a be the distance, so 14-a is the other distance.
Now to be zero amplitude, these two waves have to be 1/2 Lambda different.
Lambda= 340m/1020=.333m
lambda/2= .167m
well, (14-a)/.167-.5=a/.167
14-a-.0833=a
a=6.958m
checking this (I don't believe it)
6.958/.167=41.66 half wavelengths
(14-6.958)/.167=42.17 half wavelengths
the difference is indeed half wavelength.
check my work, I am still wondering.
Two speakers 14m apart are emitting tones at a frequency of 1020 Hz. what is the closest distance (in m) from one speaker, along the line connecting the speakers, at which the sound intensity will be zero?
1 answer
1 answer