Y = 5.07*sin60.2 = 4.40 m/s.
d = V*T = 24.7, 4.4*T = 24.7, T = 5.61 s.
Two soccer players, Mary and Jane, begin running from nearly the same point at the same time. Mary runs in an easterly direction at 4.43 m/s, while Jane takes off in a direction 60.2o north of east at 5.07 m/s. How long is it before they are 24.7 m apart?
What is the velocity of Jane relative to Mary? Enter first the x-component and then the y-component.
How far apart are they after 4.08 s?
1 answer