Two small pitchers and one large pitcher can hold 8 cups of water. One large pitcher minus one small pitcher constitutes 2 cups of water. How many cups of water can each pitcher hold?

Answer 1

large pitcher --- x
small pitcher --- y

x + 2y = 8
x - y = 2
subtract them:

3y = 6
y = 2
then x = 4

large holds 4 cups, the smaller holds 2 cups

Answer 2

I dont have these answers on my work