Question

two slabs of thickness 10cm and 2ocm are made of rteel and copper respectively.they are in thermal contact with each oth.the far end of the steel is at 100 degrees celcius amd that of copper is at 0 degrees celcius.determine the temperature at the junction and the rate of the heat transfer through each slab

Answer 1

let Tj be the junction temp
Heat flow rate=Conducivitsteel*(100-Tj)Area/.1cm

Het flow rate=conductitycopper*(Tj-0)area/.2

set the two heat rates flows equal to each other, then solve for Tj