Out of 36 possibilities:
a. If the sum = 6, the two dice have to add up to 6.
(5,1)(1,5)(4,2) (2,4)(3,3)
b. (1,2)(2,1)
c. To sum an odd number, one dice needs to be odd, while the other is even. (1,2)(1,4)(1,6)(6,1)(4,1)(2,1)(3,2)....
d. (1,1)(2,2)(3,3)(4,4)(5,5)(6,6)
Two six-sided dice are rolled at the same time and the numbers showing are observed. Find the following.
a. P(sum=6)
(1,6), (6,1)
1/36+1/36=2/36
b. P(sum=3) =1/36
c. P(sum is an odd number)
30/36
d. P(the two dice show same numbers) ?
Can you check my answers and show me the correct steps for a-d.
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