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Two similar waves X and Y travel through the same medium. Wave X has a frequency of 200 hertz and a wavelength of 35 meters. Wa...Question
Two similar waves X and Y travel through the same medium. Wave X has a frequency of 200 hertz and a wavelength of 35 meters. Wave Y has a frequency of 700 hertz. What is the wavelength for wave Y?(1 point)
Responses
122.5 meters
122.5 meters
10 meters
10 meters
4,900,000 meters
4,900,000 meters
0.1 meter
Responses
122.5 meters
122.5 meters
10 meters
10 meters
4,900,000 meters
4,900,000 meters
0.1 meter
Answers
Answered by
GPT-4o mini
To find the wavelength of wave Y, we can use the wave speed formula:
\[
v = f \times \lambda
\]
where:
- \( v \) is the wave speed,
- \( f \) is the frequency,
- \( \lambda \) is the wavelength.
First, we need to determine the wave speed using wave X:
For wave X:
- Frequency \( f_X = 200 \) Hz
- Wavelength \( \lambda_X = 35 \) meters
Calculating the wave speed (\( v \)) of wave X:
\[
v = f_X \times \lambda_X = 200 \, \text{Hz} \times 35 \, \text{m} = 7000 \, \text{m/s}
\]
Now we can use the wave speed for wave Y, which has a frequency of \( f_Y = 700 \) Hz. We will use the same wave speed:
\[
v = f_Y \times \lambda_Y
\]
Substituting the values we have:
\[
7000 \, \text{m/s} = 700 \, \text{Hz} \times \lambda_Y
\]
Now we solve for \( \lambda_Y \):
\[
\lambda_Y = \frac{7000 \, \text{m/s}}{700 \, \text{Hz}} = 10 \, \text{meters}
\]
Therefore, the wavelength for wave Y is **10 meters**.
\[
v = f \times \lambda
\]
where:
- \( v \) is the wave speed,
- \( f \) is the frequency,
- \( \lambda \) is the wavelength.
First, we need to determine the wave speed using wave X:
For wave X:
- Frequency \( f_X = 200 \) Hz
- Wavelength \( \lambda_X = 35 \) meters
Calculating the wave speed (\( v \)) of wave X:
\[
v = f_X \times \lambda_X = 200 \, \text{Hz} \times 35 \, \text{m} = 7000 \, \text{m/s}
\]
Now we can use the wave speed for wave Y, which has a frequency of \( f_Y = 700 \) Hz. We will use the same wave speed:
\[
v = f_Y \times \lambda_Y
\]
Substituting the values we have:
\[
7000 \, \text{m/s} = 700 \, \text{Hz} \times \lambda_Y
\]
Now we solve for \( \lambda_Y \):
\[
\lambda_Y = \frac{7000 \, \text{m/s}}{700 \, \text{Hz}} = 10 \, \text{meters}
\]
Therefore, the wavelength for wave Y is **10 meters**.
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