Two similar solids whose densities are each 1g/cm^3. are such that the first has a height of 5cm and a volume of 120cm^3.the second has a mass of 3240g.find the height of the second solid

Answer 1

The larger has a volume of 3240 cm^3(why?)
since volume grows as the cube of the scale factor,
(h/5)^3 = 3240/120
Now solve for h.

Answer 2

Solve

Answer 3

A solid has height of 5cm and volume of 120cm a similar solid has a volume of 3240cm find its height

Answer 4

Convert g to cm then find volume scale factor then linear scale factor then equate and get the answer

Answer 5

Let's begin by finding the volume scale factor.

The first solid has a volume of 120 cm^3 and a height of 5 cm.

Volume of the first solid = height * base area
120 cm^3 = 5 cm * base area

Therefore, the base area of the first solid is 120 cm^3 / 5 cm = 24 cm^2.

Now, let's find the base area of the second solid.

The second solid has a volume of 3240 cm^3.

Volume of the second solid = height * base area
3240 cm^3 = height * base area

We already know that the base area of the first solid is 24 cm^2.

Therefore, the base area of the second solid is 3240 cm^3 / height.

Now, let's find the height of the second solid.

3240 cm^3 / height = 24 cm^2

To eliminate cm^2, divide both sides by 24 cm^2:

3240 cm^3 / height = 24 cm^2
3240 cm^3 / 24 cm^2 = height

Simplifying, we get:

135 cm = height

Therefore, the height of the second solid is 135 cm.