d^2=(12t)^2 + (19t)^2 where t is time in hours sailing. In this case, t=1hr
solve for d.
Two ships leave the same port at noon. Ship A sails north at 12 mph, and ship B sails east at 19 mph. How fast is the distance between them changing at 1 p.m.? (Round your answer to one decimal place.)
2 answers
d^2=(12t)^2 + (19t)^2 where t is time in hours sailing. In this case, t=1hr
take the derivative
2d dd/dt=2*144t+2*19^2 t
dd/dt = relative velocity
v= (288 +261)/d
where d=sqrt(12^2+19^2)
take the derivative
2d dd/dt=2*144t+2*19^2 t
dd/dt = relative velocity
v= (288 +261)/d
where d=sqrt(12^2+19^2)
2 answers