Let's answer each of your questions one by one.
Question 1: The functions provided are \(f(x) = 2x + 3\) and \(g(x) = 0.1 \cdot 3^x\).
- The y-intercept of \(f(x)\) is \(3\) (when \(x=0\), \(f(0)=3\)).
- The y-intercept of \(g(x)\) is \(0.1 \cdot 3^0 = 0.1\) (when \(x=0\)).
- As \(x\) increases, \(f(x)\) will grow linearly while \(g(x)\) grows exponentially.
- Therefore, the graph of g(x) will eventually exceed the graph of f(x).
Answer: The graph of g(x) will eventually exceed the graph of f(x).
Question 2: The data shows:
- \(f(1) = 3\)
- \(f(2) = 5\) (difference of \(2\))
- \(f(3) = 7\) (difference of \(2\))
Since there is a common difference of \(2\), this represents a linear function.
Answer: This is a linear function because there is a common difference of 2.
Question 3: The data shows:
- \(f(1) = 22.42\)
- \(f(2) = 22.84\) (difference of \(0.42\))
- \(f(3) = 23.26\) (difference of \(0.42\))
- \(f(4) = 23.68\) (difference of \(0.42\))
The common difference here is \(0.42\).
Answer: The common difference is 0.42.
Question 4: The table shows a clear exponential decay as follows:
- \(f(0) = 100\)
- \(f(1) = 50\) (half of \(100\))
- \(f(2) = 25\) (half of \(50\))
This implies the relationship can be represented with the function \(f(t) = 100(0.5)^t\).
Answer: f(t) = 100(0.5)^t.
Question 5: To find the percent rate of growth:
- The increase from \(30\) to \(31.8\) is \(1.8\).
- The percent increase = \(\frac{1.8}{30} \times 100% = 6%\).
Answer: 6%.
Question 6: In the function \(f(t) = 3(2)^t\):
- \(t\) represents the year number.
- In year \(6\), \(f(6) = 3(2)^6 = 3 \times 64 = 192\).
Answer: t represents the year number; 192 people were recruited in year 6.
Question 7: In the function \(f(x) = 20x + 95\):
- \(f(x)\) represents the total number of pages Antonia has read.
- \(x\) represents the number of days.
Answer: f(x) represents the total number of pages Antonia has read; x represents the number of days.
Question 8: Cecelia increases her study time in equal increments (linear) while Christopher doubles his study time each week (exponential).
Answer: Christopher's method is exponential because the number of minutes increased by an equal factor every week.
Question 9: In the function \(f(x) = 2(1.25)^x\), the growth rate is the coefficient of the exponential factor minus 1:
- \(1.25 - 1 = 0.25\) or 25% growth rate.
Answer: 25%.
Question 10: To determine when \(f(x) = 2^x\) exceeds \(g(x) = 4x + 12\), evaluate both functions for increasing integer values of \(x\):
- Month 1: \(f(1) = 2\), \(g(1) = 16\) (g > f)
- Month 2: \(f(2) = 4\), \(g(2) = 20\) (g > f)
- Month 3: \(f(3) = 8\), \(g(3) = 24\) (g > f)
- Month 4: \(f(4) = 16\), \(g(4) = 28\) (g > f)
- Month 5: \(f(5) = 32\), \(g(5) = 32\) (g = f)
- Month 6: \(f(6) = 64\), \(g(6) = 36\) (f > g)
Thus, the funds in the \(f(x)\) bank account exceed those in the \(g(x)\) bank account in Month 6.
Answer: Month 6.