Two ropes are identical, a wave traveling through the first rope, has a frequency of 1.5 Hz and a wavelength of 6 m what is the frequency of a wave in the second rope if it’s wavelength is 2 m

Answer 1

To find the frequency of the wave in the second rope, we can use the formula:

frequency = wave speed / wavelength

Since the ropes are identical, their wave speed will be the same. Therefore, we can ignore the wave speed and use the formula:

frequency1 / wavelength1 = frequency2 / wavelength2

Plugging in the values we have:

1.5 Hz / 6 m = frequency2 / 2 m

Now, we can solve for frequency2:

frequency2 = (1.5 Hz / 6 m) * 2 m
frequency2 = 0.5 Hz

Therefore, the frequency of the wave in the second rope is 0.5 Hz.