To find the exposed surface area of the object when the two right triangular prisms are pushed together, we first need to calculate the surface area of each individual prism.
The surface area of a right triangular prism can be calculated by adding the areas of the two triangular bases and the three rectangular faces.
The area of the triangle base is 1/2 * base * height, so in this case, it is 1/2 * 12 * 5 = 30 cm^2.
The area of the rectangular faces can be calculated by multiplying the perimeter of the base by the height of the prism. The perimeter of the base is 12 + 12 + 2 + 2 = 28 cm. Therefore, the area of each rectangular face is 28 * 5 = 140 cm^2.
Adding the areas of the two triangular bases and three rectangular faces, we get the total surface area of each prism as 30 (two bases) + 140 (three faces) = 170 cm^2.
Since two prisms are pushed together, the total exposed surface area is 2 * 170 = 340 cm^2.
Therefore, the exposed surface area of the object when the two triangles are pushed together is 340 cm^2.
Two right triangular prisms are pushed together as
x
shown. The base of one triangle is 12 cm long and 2 cm deep. The height of the triangle is 5 cm.
b. Determine the exposed surface area of the object when the two triangles are pushed together. The answer is 220
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