To calculate the current in the circuit when the resistors are connected in parallel, you can use the formula:
1/R_total = 1/R1 + 1/R2
R1 = 16 Ω
R2 = 37 Ω
1/R_total = 1/16 + 1/37
1/R_total = 0.0625 + 0.0270
1/R_total = 0.0895
R_total = 1/0.0895
R_total = 11.17 Ω
Now, you can use Ohm's Law to calculate the current:
V = IR
I = V/R_total
I = 20 V / 11.17 Ω
I = 1.788 A
The current in the circuit is 1.788 A.
To calculate the power expended in the circuit, you can use the formula:
P = IV
P = 1.788 A * 20 V
P = 35.76 W
The power expended in the circuit is 35.76 W.
Two resistors with values of 16 Ω and 37 Ω, respectively, are connected in parallel and hooked to a 20 V batter.
What would be the current in the circuit?
____A
What would be the power expended in the circuit?
_____ W
1 answer