Two resistors of 2.0 ohm and 3.0 ohm are connected a) in series b) in parallel, with a battery of 6.0V and negligible internal resistance. For each case draw a circuit diagram and calculate the current through the battery

Answer 1

I'm sure you have seen examples of this simple circuit.

(a) R = 2+3
(b) 1/R = 1/2 + 1/3

I = E/R in each case.