Two resistors of 15ohms and 5ohms are connected in parallel.this parallel combination is connected in a series with a third resistor of 10ohms.the whole circuit is then connected across a 40 volts supply. 1.determine the resistance of the circuit. 2.the current drawn from the supply.3.the volt drop across the 10ohm resistor. 4.the volt drop across the parallel branch.5.the current flow across the 15ohms. 6.the current flow across the 10ohms resistor.

1 answer

1. R=(15*5)/(15+5) + 10=3.75 + 10=13.75 Ohms. = Resistance of the circuit.

2. I = E/R = 40/13.75 = 2.91 Amps.

3. V = I*R = 2.91 * 10 = 29.1 Volts.

4. V = I*R = 2.91 * 3.75 = 10.91 Volts.

5. I = V/R = 10.91/15 = 0.727 Amps.

6. I = V/R = 29.1/10 = 2.91 Amps.