Two resistors in series, R1 and R2, have a total resistance of 1,600 ohms. The resistance of R2 is 560 ohms less than twice R1. Find the resistance of R1 and R2.

Answer 1

Eq1: R1 + R2 = 1600 Ohms.
Eq2: R2 = 2R1 - 560 Ohms.
In Eq1, replace R2 with 2R1-560
R1 + 2R1-560 = 1600
3R1 = 2160
R1 = 720 Ohms
In Eq1, replace R1 with 720 Ohms.
720 + R2 = 1600
R2 = 880 Ohms