There are 36 possible outcomes when rolling two dice, as each die has 6 possible outcomes. To find the probability that the sum of the pips is at least 8, we need to count how many of these outcomes result in a sum that is at least 8.
One way to approach this is to list all of the possible outcomes and count how many of them have a sum of at least 8:
- (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
- (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
- (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
- (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
- (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 25 outcomes in total, and 15 of them have a sum of at least 8. Therefore, the probability of getting a sum of at least 8 is:
15/36 = 5/12
So the probability of rolling two dice and getting a sum of at least 8 is 5/12.
Two regular 6 sided dice are tossed. Compute the probability that the sum of the pips on the upward faces of the two dice is the following. At least 8
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