wow - this is a bit different from the usual ones.
Set A at (0,0). Then B is at (80,0).
Label the two aircraft C and D. We want to find CD.
AC has slope tan60° = 1.732
BC has slope tan104° = -4.011
AD has slope tan125° = -1.428
BD has slope tan157° = 0.424
So, C is at the intersection of
y = 1.732x
y = -4.011(x-80)
D is at the intersection of
y = -1.428x
y = 0.424(x-80)
So, solve for C and D, then use the normal distance formula.
two radar stations A and B are 80km apart and B is due east of A.One aircraft is on a bearing 030 from A and 346 fromB. A second aircraft is on a bearing of 325 from A and 293 from B.How far apart are the two aircraft?
4 answers
how slopes
Bye
How can we do through trigonometry while drawing scales