Let's call the time it takes for the two vats to have the same amount of liquid "t" in minutes.
After t minutes, the empty vat will have been filled with 6t gallons.
After t minutes, the other vat will have increased its amount of liquid by 4t gallons, reaching 28 + 4t gallons.
To find the time t when the two vats have the same amount of liquid, we need to solve the equation:
6t = 28 + 4t
Subtracting 4t from both sides:
2t = 28
Dividing both sides by 2:
t = 28/2
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes.
Two pumps are filling large bats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other car already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid
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1 answer