Two professional downhill skiers are racing at the speeds shown in the diagram. *Skier 1 is going 100 ft/s, and Skier 2 is going 110 ft/s. Skier 1 starts 5 seconds before Skier 2. The course is 5000 ft long. Will Skier 2 pass Skier 1?

Answer 1

5000/100 = 50
5000/110 = 45.45
so, since skier 1 started 5 seconds early, he will finish 0.55 seconds ahead

Answer 2

Thank you!

Answer 3

Can I ask why you divided the course length by the speeds?