Two pools are being filled with water. To start, the first pool contains 1090 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 17.25 liters per minute. Water is being added to the second pool at a rate of 44.5 liters per minute.

After how many minutes will the two pools have the same amount of water?

How much water will be in each pool when they have the same amount?

1 answer

Let x be the number of minutes it takes for the two pools to have the same amount of water.

At time x:
Pool 1 will have 1090 + 17.25x liters of water
Pool 2 will have 44.5x liters of water

Setting the two expressions equal gives:
1090 + 17.25x = 44.5x
Solving for x:
1090 = 44.5x - 17.25x
1090 = 27.25x
x = 40

After 40 minutes, the two pools will have the same amount of water.

Substituting x = 40 back into the expressions:

Pool 1: 1090 + 17.25(40) = 1090 + 690 = 1780 liters
Pool 2: 44.5(40) = 1780 liters

Therefore, after 40 minutes, both pools will have 1780 liters of water.