Two pool balls, each of mass 0.2kg, collide as shown in the figure above. Before the collision, the black ball’s velocity makes an angle of 30∘ with the horizontal line. After the collision, the white ball’s velocity makes an angle of 60∘ with the vertical line. What is the black ball’s speed after the collision?

Question

If needed, sin(30∘)=cos(60∘)=12,sin(60∘)=cos(30∘)=3√2,tanθ=sinθcosθ
sin(90∘+θ)=cosθ,cos(90∘+θ)=−sinθ,g=10ms2
.

Speed =- unanswered m/s

Answer 1

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