Two polygons are congruent and the perimeter of the first polygon is 38 cm. If the sides of the second polygon are consecutive integers (x, x+1, x+2, x+3, etc.), what value of x makes the polygons into congruent quadrilaterals? Use x as the smallest side.

Answer 1

Congruent figures have the same perimeters.

Quadrilaterals have four sides.

The perimeters of both would be 4x + 6.
Since 4x = 6 = 38, x = 8.
The side lengths are 8, 9, 10, and 11.

I don't see why the bring a second quadrilateral into the discusion.