since F = q1*q2 / r^2
if r changes to 3r, the force goes down to 1/9 as much
(3r)^2 = 9r^2
Two point charges, q1 and q2, are located at a distance r apart in a vacuum. The electric force between them is F. What will the electric force become if the distance between the charges in tripled?
A. F/9
B. 9F
C. 3F
D. F/3
1 answer