field strength is proportional to the charge
... and inversely proportional to the square of the distance
d is the distance from the origin along the x-axis
10 / d^2 = 2 / (4 - d)^2
10 (4 - d^2) = 2 d^2
40 = 12 d^2
Two point charges Q1 = 10µc and Q2 = 2µc are arranged along the x-axis at
x = 0 and x=4m respectively. Find the position along the x-axis where v = 0.
1 answer