E=k(3/d^2 +2/d^2) where d is the half distance
E=k(5/d^2) now d=.01m so
E=k(5E-4) N/C
Two point charges of magnitude +3.0 nC and +2.0 nC respectively are placed 2.0cm apart. Calculate the resultant electric field strength at their midpont
E= E1 + E2
1 answer