Your first number is the E-field due to each charge. You have to double it, since they are both in the same direction.
For the second case,
8.99*10^9*q^2/(3.7*10^-10)^2 = 2.37*10^-3
q^2 = 3.61*10^032 C^2
q = 1.90*10^-16 C
I agree with your answer.
Two point charges are 10.0 cm apart and have charges of 2.0 μC and –2.0 μC, respectively. What is the magnitude of the electric field at the midpoint between the two charges?
8.99*10^9(2*10^-6/.025)=719200
Two equal charges are separated by 3.7 x 10-10 m. The force between the charges has a magnitude of 2.37 x 10-3 N. What is the magnitude of q on the charges?
1.9x10^-16 (I got this using Coulomb's Law and working backward)
Thanks in advance!
3 answers
Great! Thank you!
Wait, can you please explain the first answer? What am I supposed to double? And after I double it, do I do what I did originally?
1 answer