since time = distance/speed, if the slower plane has speed s, we have
3600/s = 3600/(s+200) + 1.5
Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The speed of one of the planes was 200 km/hour slower than the speed of the other plane, and so it arrived at its destination 1.5 hours after the faster plane. Find the speeds of both planes.
9 answers
f is faster speed , s is slower speed
f = s + 200
3600 / s = (3600 / f) + 1.5 ... 3600 f = 3600 s + 1.5 f s
substituting ... 3600 s + 720000 = 3600 s + 1.5 s^2 + 300 s
s^2 + 200 s - 480000 = 0
solve for s , substitute back to find f
f = s + 200
3600 / s = (3600 / f) + 1.5 ... 3600 f = 3600 s + 1.5 f s
substituting ... 3600 s + 720000 = 3600 s + 1.5 s^2 + 300 s
s^2 + 200 s - 480000 = 0
solve for s , substitute back to find f
600
and 800
yes he is right. Its going to be 600 and 800
cool
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2 answers