rate=distance/time
2700/*=2025/y
2700/*=2025/*-1.5,
*diferent from 0,1.5
*=6hrs & y=4.5hrs
Two planes leave an airport flying at the same rate.If the first plane flies 1.5 hours longer than the second plane and travels 2700 miles while the second plane travels only 2025 miles,
for how long was each plane flying?
8 answers
Let their rate be x mph
time for first = 2700/x
time for second = 2025/x
2700/x - 2025/x = 1.5
times x
2700 - 2025 = 1.5x
x = 450
so the first flew for 2700/450 hrs or 6 hrs
a nd the 2nd flew for 2025/450 or 4.5 hrs
notice the difference is 1.5 hrs
time for first = 2700/x
time for second = 2025/x
2700/x - 2025/x = 1.5
times x
2700 - 2025 = 1.5x
x = 450
so the first flew for 2700/450 hrs or 6 hrs
a nd the 2nd flew for 2025/450 or 4.5 hrs
notice the difference is 1.5 hrs
Thank You! and
my answer and your answer are the same
my answer and your answer are the same
It is just that your text came out weird.
What's with all the * symbols all over the place?
What's with all the * symbols all over the place?
* this symbols multiply
yup, that's what it means.
So what is " *diferent from 0,1.5 " and " 2700/*=2025/*-1.5, " ???
That's what I was objecting to.
So what is " *diferent from 0,1.5 " and " 2700/*=2025/*-1.5, " ???
That's what I was objecting to.
excuse me
* this symbols star
* this symbols star
Yes the answer is 6hrs& 4.5hrs exact answer