Two planes are initially separated by a horizontal distance of 350 km. Plane A is positioned 350 km west of the Plane B. Plane A is initially traveling at a velocity of 60 m/s east. Plane B is traveling at a velocity of 45 m/s west.

Question

If plane A begins to accelerate east at a rate of 5 m/s2 when the planes are 350 km apart, how long will it take the planes to meet assuming plane B maintains a constant speed?

Ok do you set it up using the .5at^2+vit=D equation to see where Plane A will meet Plane or is another one to be used??

Thank you so much!

Answer 1

When they meet:
Da + Db = 350 km.
60*T+0.5*a*T^2 + 45*T = 350.

a = 5 m/s^2.
T = ?

Answer 2

Thank you!!