The sums of torques respectively the edges of the board are:
W•x-400•2 = 0
W• (2-x) -700•2=0
W•x=800
2W-W•x -1400 = 0
2W-800-1400=0
W=1100 N
x=800/W =0.73 m
two people carry a heavy electric motor by placing it on a light board 2m long.one person lifts at one end with a force of 700N, and the other lifts the opposite end with a force of 400N.Calculate the weight of the motor and determine where its center of Gravity is Located
1 answer
1 answer