Two people carry a heavy electric motor by placing it

on a light board 2 meter in length. One person lifts at
one end with a force of 700N, and the other lifts the
opposite end with a force of 500N. What is the weight
of the motor, where along the board is its centre of
gravity located?

2 answers

weight = 700N + 500N

measuring distance (d) from the 500N end ... d(700 + 500) = 2 * 700
the weight is equal and opposite to the total force up.
Hey, enough already, read the text.