two particles moving along x-axis in the same direction with uniform velocity is 8 metre per second and 4 metre per second initially the first particle is 21 m to the left of the origin and the second one is 7 m to the right of the origin to particle meets from the origin at a distance of

Answer 1

particle 1
x = -21 + 8 t
particle 2
x = 7 + 4 t
so
-21 + 8 t = 7 + 4 t

4 t = 28
t = 4 seconds
x = 7 + 16 = 23

Answer 2

1 st particle
x+21=u¹t
21+x=8t
x=-21+8t....
2 nd particle
x-7=u²t
x=7+4t
equating 1st and 2 nd particles
-21+8t=7+4t
8t-4t=21-7
4t=28
t=28/4 = 7 sec
SUBSTITUTION
x=-21+8t
x=-21+8(7)
x= -21+56=35
(or)
x=7+4t
x=7+4(7)
x=7+28=35

Answer 3

Correct 😀😀

Answer 4

nice solution very easy understanding thanks

Answer 5

Very nice answer bro

Answer 6

Why u took x plus 21=u1t