F1 = m*g = 10.89kg * 9.8N/kg = 106.7 N.
F2 = 2.59kg * 9.8N/kg = 25.4 N.@ 40o.
Fp = 25.4*sin40 = 16.3 N. = Force paral-
lel to incline.
a. Fn = F1 - Fp = m*a.
106.7-16.3 = 2.59*a
90.4 = 2.59*a
a = 90.4 m/s^2.
Two packing crates of masses 10.89 kg and 2.59 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 2.59 kg crate lies on a smooth incline of angle 40.0°.
a) Find the acceleration of the 2.59 kg crate
B) find tension in the string
1 answer