Two organ pipes, open at one end but closed at the other, are each. 1.14 m long. One is now lengthened by 2.00 cm. Find the frequency of the beat they produce when playing together in their fundamental.

Question

Paul · Accepted Answer

f1=(344m/s) / (4*1.14m)=75.4386Hz f2=(344m/s) / (4*(1.14m+.02m))=74.1379Hz f=f1-f2=1.3007Hz

Anonymous · Answer

34

Grant · Answer

Going to be about 1-2 hertz fyi, 345/pipe1 345/pipe2 and difference