Question

Two objects in a closed system collide while moving directly toward each other. Each has a mass of 1.00 kg and is moving at 1.80 m/s. What is the total momentum after the collision?(1 point) Responses 0.90 kg·m/s 0.90 kg·m/s 3.60 kg·m/s 3.60 kg·m/s 0.00 kg·m/s 0.00 kg·m/s 1.80 kg·m/s

Answer 1

To find the total momentum after the collision, we first need to calculate the total momentum before the collision.

Momentum (p) is given by the formula:

\[ p = m \times v \]

where \( m \) is the mass and \( v \) is the velocity.

Before the collision, we have:

- Object 1: mass = 1.00 kg, speed = 1.80 m/s (to the right, let's say this is positive)
- Object 2: mass = 1.00 kg, speed = -1.80 m/s (to the left, this is negative)

Calculating the momentum for each object:

1. **Object 1:**
\[ p_1 = 1.00 \, \text{kg} \times 1.80 \, \text{m/s} = 1.80 \, \text{kg·m/s} \]

2. **Object 2:**
\[ p_2 = 1.00 \, \text{kg} \times (-1.80 \, \text{m/s}) = -1.80 \, \text{kg·m/s} \]

Now, we can find the total momentum before the collision:

\[
\text{Total momentum} = p_1 + p_2 = 1.80 \, \text{kg·m/s} + (-1.80 \, \text{kg·m/s}) = 0.00 \, \text{kg·m/s}
\]

In a closed system, the total momentum before a collision equals the total momentum after the collision. Since the total momentum before the collision is 0.00 kg·m/s, the total momentum after the collision will also be:

\[
\text{Total momentum after the collision} = 0.00 \, \text{kg·m/s}
\]

Thus, the correct answer is **0.00 kg·m/s**.