To find the total momentum after the collision, we first need to calculate the total momentum before the collision.
Momentum (p) is given by the formula:
\[ p = m \times v \]
where \( m \) is the mass and \( v \) is the velocity.
Before the collision, we have:
- Object 1: mass = 1.00 kg, speed = 1.80 m/s (to the right, let's say this is positive)
- Object 2: mass = 1.00 kg, speed = -1.80 m/s (to the left, this is negative)
Calculating the momentum for each object:
-
Object 1: \[ p_1 = 1.00 , \text{kg} \times 1.80 , \text{m/s} = 1.80 , \text{kg·m/s} \]
-
Object 2: \[ p_2 = 1.00 , \text{kg} \times (-1.80 , \text{m/s}) = -1.80 , \text{kg·m/s} \]
Now, we can find the total momentum before the collision:
\[ \text{Total momentum} = p_1 + p_2 = 1.80 , \text{kg·m/s} + (-1.80 , \text{kg·m/s}) = 0.00 , \text{kg·m/s} \]
In a closed system, the total momentum before a collision equals the total momentum after the collision. Since the total momentum before the collision is 0.00 kg·m/s, the total momentum after the collision will also be:
\[ \text{Total momentum after the collision} = 0.00 , \text{kg·m/s} \]
Thus, the correct answer is 0.00 kg·m/s.