Two normads leaves camp at the same time,one travel 5km/h on a bearing of 39 degree and the other travel 7.5km/h on a bearing of 265 degree.how far are apart and what is the bearing of the second from the first?

Answer 1

"how far are apart" ?
After what time ?

Let the time passed since they left be t hours
My diagram shows a triangle with sides 5t and 7.5t and an angle of 134° between those sides.

If the distance between them is x, by the cosine law:
x^2 = (5t)^2 + (7.5t)^2 - 2(5t)(7.5t)cos134°
= 25t^2 + 56.25t^2 - (-52.01 t^2)
x^2 = 133.35 t^2
x = √133.35 t
x = appr 11.55 t km