Asked by kristen
Two neutron stars are separated by a distance of 10^14 m. They each have a mass of 10^30 kg and a radius of 10^5 m. They are initiall at rest with respect to each other.
How fast are they moving when their seperation has decreased to one-half its initial value?
How fast are they moving before they collide?
How fast are they moving when their seperation has decreased to one-half its initial value?
How fast are they moving before they collide?
Answers
Answered by
drwls
Let R be the initial separation and r be thr radius of each.
The initial potential energy is
PE1 = -GM^2/R
When the separation is R/2, the potential energy is
PE2 = -2GM^2/R
The reduction in potential energy, GM/R^2, is converted to kinetic energy equal to
2 *(1/2) M V^2, where V is the velocity of each towards the center of mass. Solve for V
V^2 = GM/R
V= sqrt(GM/R)
G is the universal constant of gravity.
When they collide, the potential energy reduction is
GM^2[(1/r) - (1/R)]
Set that equal to 2(1/2) M V'^2 for the velocity of each, V'.
If it is close to the speed of light, a relativistic equation should have been used.
The initial potential energy is
PE1 = -GM^2/R
When the separation is R/2, the potential energy is
PE2 = -2GM^2/R
The reduction in potential energy, GM/R^2, is converted to kinetic energy equal to
2 *(1/2) M V^2, where V is the velocity of each towards the center of mass. Solve for V
V^2 = GM/R
V= sqrt(GM/R)
G is the universal constant of gravity.
When they collide, the potential energy reduction is
GM^2[(1/r) - (1/R)]
Set that equal to 2(1/2) M V'^2 for the velocity of each, V'.
If it is close to the speed of light, a relativistic equation should have been used.
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