To determine the minimum force the second mover needs to apply to push the couch up the ramp, we can analyze the forces acting on the couch.
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Identify the forces:
- The first mover applies a force of \( F_1 = 80 , \text{N} \) to the right (up the ramp).
- The friction force acting against the motion is \( F_f = 110 , \text{N} \) (down the ramp).
- Let the force applied by the second mover be \( F_2 \) (also acting up the ramp).
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Net force required to move up the ramp: For the couch to move up the ramp, the total force acting up the ramp must overcome the friction force. Therefore, we can set up the equation:
\[ F_1 + F_2 > F_f \]
- Substituting the known values: Replacing \( F_1 \) and \( F_f \) gives:
\[ 80 , \text{N} + F_2 > 110 , \text{N} \]
- Rearranging the inequality: To find the minimum force \( F_2 \):
\[ F_2 > 110 , \text{N} - 80 , \text{N} \]
\[ F_2 > 30 , \text{N} \]
- Final result: Therefore, at minimum, the second mover needs to apply a force greater than \( 30 , \text{N} \) to help push the couch up the ramp.
Thus, the answer is that the second mover needs to apply at least 31 N (since the force must be greater than 30 N) to ensure the couch moves up the ramp.