a. d1=.5 (2)t^2
d2=.5 (3)t^2 +24
but d1=d2 then
put d1, d2 in and solve for time t.
b. use the d2 equation
c.v2=3*t^2
Two motorcycles are at rest and are separated by 24 ft they start at the same time and same direction , the one in the back is having acceleration 3 ft/ sec^2 and the one in front is 2 ft/sec^2 can be machine at the back overtake in front?
A. How long thus it takes to overtake?
B. How far this is goes before it cathes up?
C. How fast its machine going at the same time on overtaking?
1 answer