Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)

Question

12x−210=15x−180

12x+210=15x+180

12x+180=15x+210

210−12x=180−15x

Answer 1

12x + 210 = 15x + 180

Answer 2

Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point) Responses 92−16x=104−13x ; x=−4 92 minus 16 x equals 104 minus 13 x ; x equals negative 4 104+16x=92+13x ; x=4 104 plus 16 x equals 92 plus 13 x ; x equals 4 92+16x=104+13x ; x=4 92 plus 16 x equals 104 plus 13 x ; x equals 4 92+16x=104+13x ; x=6

Answer 3

92 - 16x = 104 - 13x
3x = 12
x = 4

Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.