Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup. (1 point)

О 92 + 16х = 104 + 13x : x = 6
092-162=104-130:2=-4
0 92 + 16x - 104 - 13x : x = 4
• 104 + 16х - 92 + 13х; x = 4

1 answer

92 + 16x = 104 + 13x
92 - 104 = 13x - 16x
-12 = -3x
x = 4

So, the two machines will have filled the same number of cans of soup after 4 minutes.
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