Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.

Question

Responses
104+16x=92+13x ; x=4
104 plus 16 x equals 92 plus 13 x ; x equals 4

92+16x=104+13x ; x=6
92 plus 16 x equals 104 plus 13 x ; x equals 6

92+16x=104+13x ; x=4
92 plus 16 x equals 104 plus 13 x ; x equals 4

92−16x=104−13x ; x=−4

Answer 1

92 minus 16 x equals 104 minus 13 x ; x equals -4