Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)

Responses

12x+210=15x+180
12 x plus 210 equals 15 x plus 180
12x−210=15x−180
12 x minus 210 equals 15 x minus 180
12x+180=15x+210
12 x plus 180 equals 15 x plus 210
210−12x=180−15x

1 answer

12x + 210 = 15x + 180
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