Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point) Responses 1.92+16x=104+13x ; x=6

Question

2.92 + 16x = 104 + 13x; x equals 6
3.92−16x=104−13x; x=−4 92 - 16 x = 104 -13x; x = -4
or
4.104+16x=92+13x; x=4

Answer 1

2. 92 + 16x = 104 + 13x; x equals 6

Therefore, the two machines will have filled the same number of cans of soup after 6 minutes.