92 + 16x = 104 + 13x
Subtract 13x from both sides:
92 + 3x = 104
Subtract 92 from both sides:
3x = 12
Divide by 3:
x = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.
Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point) Responses 92+16x=104+13x ; x=6 92 plus 16 x equals 104 plus 13 x ; x equals 6 92−16x=104−13x ; x=−4 92 minus 16 x equals 104 minus 13 x ; x equals negative 4 104+16x=92+13x ; x=4 104 plus 16 x equals 92 plus 13 x ; x equals 4 92+16x=104+13x ; x=4
3 answers
Movie Theatre A has a popcorn machine with a 120-gallon capacity. It sells 7 gallons of popcorn per hour. Movie Theatre B has a popcorn machine with a 150-gallon capacity. It sells 9 gallons of popcorn per hour. Write and solve an equation to show when the two popcorn machines will have the same amount of popcorn left.(1 point) Responses 120−7x=150−9x ; x=10 120 minus 7 x equals 150 minus 9 x ; x equals 10 120x−7=150x−9 ; x=15 120 x minus 7 equals 150 x minus 9 ; x equals 15 120+7x=150+9x ; x=−15 120 plus 7 x equals 150 plus 9 x ; x equals negative 15 120−7x=150−9x ; x=15
120 - 7x = 150 - 9x
Add 9x to both sides:
120 + 2x = 150
Subtract 120 from both sides:
2x = 30
Divide by 2:
x = 15
Therefore, the two popcorn machines will have the same amount of popcorn left after 15 hours.
Add 9x to both sides:
120 + 2x = 150
Subtract 120 from both sides:
2x = 30
Divide by 2:
x = 15
Therefore, the two popcorn machines will have the same amount of popcorn left after 15 hours.
1 answer